Chemistry College

## Answers

**Answer 1**

**Answer:**

**Percent yield = 16.95%.**

**Explanation:**

Let's write the balanced equation:

[tex]LiOH+KCl\rightarrow LiCl+KOH.[/tex]

We want to know the theoretical yield of lithium chloride (LiCl), we want to know how much we will produce of this compound from 20 g of lithium hydroxide; so the first step is to convert 20 g of lithium hydroxide (LiOH) to moles using its molar which is 23.9 g/mol (you can calculate the molar mass of a compound using the periodic table). The conversion will look like this:

[tex]20\text{ g LiOH}\cdot\frac{1\text{ mol LiOH}}{23.9\text{ g LiOH}}=0.837\text{ moles LiOH.}[/tex]

You can see in the chemical equation that 1 mol of LiOH reacted produces 1 mol of LiCl, so the molar ratio between them is 1:1, which means that 0.837 moles of LiOH reacted produces 0.837 moles of LiCl.

The next step is to convert 0.837 moles of LiCl to grams using its molar mass which is 42.3 g/mol:

[tex]0.837\text{ moles LiCl}\cdot\frac{42.3\text{ g LiCl}}{1\text{ mol LiCl}}=35.4\text{ g LiCl.}[/tex]

35.4 g LiCl would be our theoretical yield. 6 grams of LiCl that are being produced is the actual yield, so to calculate the percent yield, we use the following formula:

[tex]\%\text{ yield =}\frac{actual\text{ yield}}{theoretical\text{ yield}}\cdot100\%[/tex]

And finally, we replace the given data on it:

[tex]\%\text{ yield=}\frac{6\text{ g}}{35.4\text{ g}}\cdot100\%=16.95\%.[/tex]

**The percent yield is 16.95%.**

## Related Questions

Calculate the number of formula units of KBr in 16.4 moles6.643.67x10229.87x10241786

### Answers

The formula units corresponds to the molecules of a substance, there is a relationship between moles and molecules, this relationship is Avogadro's number.

Avogadro's number tells us that a mole of any substance contains 6.022x10^23 molecules. Therefore in 16.4 moles of Kbr there will be:

[tex]\begin{gathered} \text{Formula units}=\text{Given moles}\times\frac{6.022\times10^{23}molecules}{1\text{ mol}} \\ \text{Formula units}=16.4\text{mol}\times\frac{6.022\times10^{23}molecules}{1\text{ mol}}=9.87\times10^{24}formulaunits \end{gathered}[/tex]

**The number of formula units of Kbr in 16.4 moles is 9.87x10^24**

A chemist prepares a sample of hydrogen bro-mide and finds that it occupies 238 mL at 66°C and 513 Torr.What volume would it occupy at O°C at the same pressure?Answer in units of mL.

### Answers

**Answer:**

[tex]191.68\text{ mL}[/tex]

**Explanation:**

Here, we want to get the final volume

From the general gas equation, we have it that:

[tex]\frac{P_1V_1}{T_1}\text{ = }\frac{P_2V_2}{T_2}[/tex]

From the question, we have it that:

P1 is the initial pressure which is 513 torr

V1 is the initial volume which is 238 mL

T1 is the initial temperature which we have to convert to absolute value by adding 273.15 K ( 66 + 273.15 = 339.15 K)

P2 is the final pressure that is the same as the initial which is 513 torr

V2 is the final volume that we want to calculate

T2 is the final temperature which is 273.15 K (0 degrees Celsius is 273.15 K)

Substituting the values, we have:

[tex]\begin{gathered} \frac{513\times238}{339.15}\text{ = }\frac{513\times V_2}{273.15} \\ \\ V_2\text{ = }\frac{513\times238\times273.15}{339.15\text{ }\times\text{ 513}}\text{ = 191.68 mL} \end{gathered}[/tex]

We could have solved this by using Charles' law that relates temperature to volume (volume is directly proportional to temperature)

How would the acidity of rice wine cause lead poisoning?

### Answers

Rice grown from contaminated soil with Lead can cause lead poisoning when consumed without first removing this heavy metal (Lead). So what happens is that human activities such as mining may lead to environmental contamination with Lead which is very dangerous to human health. When this metal is consumed in

If you have 1.23 L of 0.347 M KNO2, 11.0 g of Al, and 1.89 L of 3.2 M NaOH, what mass of NH3 can be produced?

### Answers

The **mass** of NH₃that can be produced is 5.49 g.

What is the mole of the reactants present in the given solution?

The **moles** of reactants in the given solutions are calculated using the formula given below as follows:

Moles = molar concentration * volume in liters

For KNO₂:

Volume = 1.23 Liters

molar concentration = 0.347 M

Moles = 1.23 * 0.347

**Moles** = 0.427 moles

For Al:

Moles = mass / molar mass

Moles = 11 / 27

moles = 0.407 moles

For NaOH:

Volume = 1.89 Liters

molar concentration = 3.2 M

**Moles** = 1.89 * 3.2

Moles = 6.048 moles

Equation of reaction:

NO₂⁻ (aq) + 2 Al (s) + H₂O (l) + OH⁻ (aq) → NH₃ (g) + 2 AlO₂⁻ (aq)

Al is the **limiting reactant**

Moles of NH₃ produced = 0.407/2 moles

Mass of NH₃ produced = 0.407/2 * 17

**Mass** of NH₃ produced = 5.49 g

Learn more about **moles** at: https://brainly.com/question/13314627

#SPJ1

Convert .9989g/ml to units kg/m^3

### Answers

Answer:

[tex]998.9\operatorname{kg}/m^3[/tex]

Explanations:

Given the measured value **of 0.9989g/ml**. We are to** convert** the value to **kg/m^3**

Using the **conversion factor** as shown:

[tex]\begin{gathered} 1000\text{grams}=1\operatorname{kg} \\ 1ml=10^{-6}m^3 \end{gathered}[/tex]

Applying this** conversion** to the given value:

[tex]\begin{gathered} =\frac{0.9989\cancel{g}}{\cancel{ml}}\times\frac{1\operatorname{kg}}{1000\cancel{g}}\times\frac{1\cancel{ml}}{10^{-6}m^3} \\ =0.9989\times\frac{1\operatorname{kg}}{10^3}\times\frac{1}{10^{-6}m^3} \\ =0.9989\times\frac{1\operatorname{kg}}{10^{3-6}m^3} \\ \end{gathered}[/tex]

**Simplifying further** will give:

[tex]\begin{gathered} =0.9989\times\frac{1\operatorname{kg}}{10^{-3}m^3} \\ =0.9989\times\frac{1000\operatorname{kg}}{m^3} \\ =998.9\operatorname{kg}m^{-3} \end{gathered}[/tex]

Hence the **required measurement** in kg/m^3 is **998.9kg/m^3**

A chemist determines by measurement that 0.0900 moles of iodine solid participate in a chemical reaction. Calculate the mass of iodine solid that participates. Be sure your answer has the correct number of significant digits

### Answers

We have 0.0900 moles of iodine solid which formula is I2

------------------------------------------------------------------------------------

Molecular weight = 253.8089 g/mol

------------------------------------------------------------------------------------

We are going to use this:

[tex]\begin{gathered} \text{Moles = }\frac{\text{grams}}{\text{molecular weight}} \\ \text{Moles x Molecular weight = grams} \\ 0.0900\text{ moles x 253.8089 }\frac{g}{\text{mol}}=22.8428g_{} \end{gathered}[/tex]

Answer: **Mass of iodine solid = 22.8428 g**

Directions: Write the balanced equation for each of the following situations. . In addition, list the reaction type. YOU MUST TELL THE AMOUNTS OF EVERY SUBSTANCE THAT REMAINS IN THE CONTAINER AT THE END OF THE REACTION. ASSUME THAT ALL REACTIONS GO TO COMPLETION. If only STOICHIOMETRY, tell how much of the excess reactant is used!!!! Reaction Type a. Combination Reaction b. Decomposition Reaction c. Single Displacement / THIS IS ONE TYPE OF Oxidation Reduction Reaction d. Precipitation Reaction e. Gaseous Reaction f. Neutralization Reaction g. Combustion Reaction 2. 61.802 cg of nitrogen gas is reacted with 61.802 cg of hydrogen gas to form ammonia 2. Balanced Chemical Equation Reaction Type: At the completion of reactions: Grams of nitrogen: Grams of hydrogen: Grams of ammonia:

### Answers

[tex]3H_2+N_2\rightarrow2NH_3[/tex]

Reaction type: Combination (or Synthesis) reaction.

We are given:

mass of N2 = 61.802 cg = 0.61802g

mass of H2 = 61.802 cg = 0.61802g

Lets start by calculating the number of moles of N2 and H2.

For N2:

n = m/M where m is the mass and M is the molar mass

n = 0.61802g/28.0134

n = 0.0218 mol

For H2:

n = m/M

n = 0.61802g/2.01588

n = 0.07977 mol

So to know which one is the excess reactant, we have to divide the moles by thier respective co-efficient.

For N2: 0.0218 mol/1 = 0.0218

For H2: 0.07977 mol/3 = 0.0266

Therefore H2 is the excess reagent. Therefore the limiting reagent is N2 so we will use it to calculate the mass of NH3 produced, because the limiting reagent in a chemical reaction is the reactant that will be consumed completely. Once there is no more of that reactant, the reaction cannot proceed.

Masses after the reaction: We will use the stoichiometry to calculate these masses.

The molar ratio between N2 and NH3 is 1:2, therefore number of moles of NH3 is = 0.0218 x 2 = 0.0436 mol

mass of NH3 = n x M

m = 0.0436 mol x 17,031 g/mol

**m = 0.743 g of NH3**

Initially we had a mass of 0.61082g H2 and 0.61082 g N2 = 1.222g

mass produced is 0.743g which means 1.222 g-0.743g = 0.478g

Since H2 is the excess reactant, after the reaction there is **0.478g of H2**

and all of N2 was used up since it is the limiting reagent. **N2 = 0g after reaction**.

Why is subatomic particles not made up of atoms

### Answers

The atom itself is not the smallest known particle, but instead each atom is made up of three individual parts: electrons, protons and neutrons. Furthermore, protons and neutrons themselves are made up of even smaller parts called quarks.

Atoms are not considered the smallest particles of an element upon recent deliberations. An element has to be an atom, because individual protons, neutrons and electrons aren't elements.

6. You have 5 moles of Mn(SO4)2. How many grams are present?

### Answers

To make the change from moles to grams we must use the molar mass of the compound. To find the molar mass we must add the atomic masses of each element present in the molecule. We make the following table:

Molar Mass = 54.938+64.13+127.992=247.063g/mol

Now, the grams in moles will be found by multiplying the given moles by the molar mass:

[tex]\begin{gathered} gMn(SO_4)_2=molMn(SO_4)_2\times\frac{247.063gMn(SO_4)_2}{1molMn(SO_4)_2} \\ gMn(SO_4)_2=5Mn(SO_4)_2\times\frac{247.063gMn(SO_4)_2}{1molMn(SO_4)_2}=1235.3gMn(SO_4)_2 \\ gMn(SO_4)_2=1\times10^3gMn(SO_4)_2 \end{gathered}[/tex]

**In 5 moles of Mn(SO4)2 there are 1x10^3 g Mn(SO4)2**

What is the pH if [H+]=6.3*10^ -5 ?

### Answers

**Explanation:**

The pH is a measure of the basicity or acidity of an aqueous solution.

We can determine the pH like this:

**pH = -log [H+]**

We know the concentration of H+ of our solution. So we have to take the -log of that value.

**[H+] = 6.3 * 10^(-5)**

pH = -log [H+]

pH = -log (6.3 * 10^(-5))

**pH = 4.2 **

**Answer:**** the pH is 4.2.**

What correctly identifies the relationship between the type of bond formed and the electronegativity of the atoms?

### Answers

Remember that electronegativity measures the type of bond formed. When the electronegativity is above 1.7 it represents an ionic bond when the electronegativity is between 0.4 and 1.7 consists of a polar covalent bond, and when the electronegativity is under by 0.4 the bond is a polar non-covalent, so **the answer is A: if the electronegativity difference between two atoms is above 1.7, the bond is ionic.**

Drag each conversion factor to the arrow that indicates where it should be used

### Answers

**Explanation:**

mass ----> moles ---> representative particles:

To go from mass to moles we usually use the molar mass of the substance or compound that we are working with. Molar mass is expressed in g/mol, so we divide by the molar mass.

mass --> moles: g * **1** **mol/(number of g)** = mol

To go from moles to representative particles we use Avogadro's number. There are 6.02 *10^23 particles in 1 mol of particles.

moles ---> particles: moles * **6.02 * 10^23 particles /(1 mol)** = particles

Then to go from particles to moles we do something similar.

particles---->moles: particles * **1 mol/(6.02 * 10^23 particles) ** = moles

And to go from moles to grams, instead of dividing by the molar mass we multiply by it.

moles --> mass: moles * **number of g/(1 mol)** = g

**Answer:**

mass ---->** 1 mol/(number of g) **---> moles --->** 6.02 * 10^23 particles /(1 mol) -**---->particles

mass <---**number of g/(1 mol) **<----- moles <----**1 mol/(6.02 * 10^23 particles)<**----- particles

A spherical weather balloon has a volume of 12.0 dm3 when inflated at STP. Assuming it could stay anchored and intact, as a hurricane passed overhead lowering the pressure to 720 mm Hg, what would be the new volume of the balloon assuming the temperature stays at 0°C?

### Answers

ANSWER

The final volume of the balloon is **12.67L**

**EXPLANATION**

Given that;

The initial volume of the ballon is 12dm^3

The initial temperature at STP is 273.15 degrees Celcius

The initial pressure at STP is 760 mmHg

The final temperature is 0 degrees Celcius

The final volume is 720 mmHg

Follow the steps below to find the new volume of the balloon

Step1; Write the general gas law equation

[tex]\text{ }\frac{\text{ P1 V1}}{\text{ T1}}=\text{ }\frac{\text{ P2V2}}{\text{ T2}}[/tex]

Step 2; Convert the volume and temperature to liters and degrees Kelvin

[tex]\begin{gathered} \text{ 1dm}^3\text{ }=\text{ 1L} \\ \text{ Hence, 12dm}^3\text{ is equivalent to 12L} \\ \\ \text{ The final temperature is 0}\degree C \\ \text{ T = t + 273.15} \\ \text{ T = 0 + 273.15} \\ \text{ T = 273.15K} \end{gathered}[/tex]

Step 3; Substitute the given data into the formula above to find the final volume

[tex]\begin{gathered} \text{ }\frac{\text{ P1V1}}{\text{ T1}}\text{ }=\text{ }\frac{\text{ P2 V2}}{\text{ T2}} \\ \\ \text{ }\frac{760\times\text{ 12}}{273.15}\text{ }=\frac{720\times V2}{273.15} \\ \text{ Cross multiply} \\ \text{ 760 }\times\text{ 12 }\times\text{ 273.15 }=\text{ 720 }\times\text{ V2 }\times\text{ 273.15} \\ \text{ Isolate V2} \\ \text{ V2 }=\text{ }\frac{760\text{ }\times\text{ 12}\times\text{ 273.15}}{720\text{ }\times\text{ 273.15}} \\ \text{ } \\ \text{ V2}=\frac{760\times12\times\cancel{273.15}}{720\times\cancel{273.15}} \\ \text{ } \\ \text{ V2 }=\text{ }\frac{9120}{720} \\ \text{ V2 = 12.67L} \end{gathered}[/tex]

Hence, the final volume of the balloon is **12.67L**

What is ΔH(rxn)? and it is formula

### Answers

**Answer:**

**Explanation:**

Here, we want to give a definition

Delta H of a reaction is the change in ethalpy that occurs at the end of the reaction. It is the end result of heat changes that occur in a chemical reaction

It describes what occurs at the end of the reaction

For instance, it is negative for an exothermic reaction which indicates that heat is given off. It is positive for an endothermic reaction, meaning heat is absorbed

Mathematically:

[tex]\Delta H_{rxn}\text{ = }\Sigma\text{ \lparen}\Delta H_{products})\text{ - }\Sigma(\Delta H_{reactants})[/tex]

Under certain conditions, the substance ammonium chloride can be broken down to form ammonia and hydrogen chloride.If 32.7 grams of ammonium chloride react to form 10.4 grams of ammonia, how many grams of hydrogen chloride must simultaneously be formed?

### Answers

**Answer**:

22.3g of hydrogen chloride are formed.

**Explanation**:

**1st) **It is necessary to write and balance the chemical reaction:

[tex]\begin{gathered} NH_4Cl\rightarrow NH_3+HCl \\ \end{gathered}[/tex]

From the balanced reaction we know that 1 mole of ammonium chloride (NH4) produces 1 mole of ammonia (NH3) and 1 mole of hydrogen chloride (HCl).

**2nd) **Using the molar mass of NH4Cl (53.5g/mol) and HCl (36.5g/mol), we can convert moles into grams.

Now we know that 53.5g of NH4Cl (1 mole) produces 36.5g of HCl (1 mole).

**3rd)** Finally, using the given value of ammonium chloride (32.7g) and with a mathematical rule of three we can calculate the grams of HCl that will be formed:

[tex]\begin{gathered} 53.5gNH_4Cl-36.5gHCl \\ 32.7gNH_4Cl-x=\frac{32.7gNH_4Cl*36.5gHCl}{53.5gNH_4Cl} \\ x=22.3gHCl \end{gathered}[/tex]

So, **22.3g of hydrogen chloride are formed**.

Sorry I’m lazy the question & choices are in the picture

### Answers

Remember that a Brønsted-Lowry acid is a molecule or ion that donates a hydrogen ion in a reaction and a Brønsted-Lowry base is a molecule or ion that accepts a hydrogen ion in a reaction.

In this case, you can see that ammonium ion is donating hydrogen to the compound HSO3 (-).

**NH4 (+) acts as Bronsted-Lowry acid because it releases a proton (H) to become NH3. The answer is 2.**

Which measurements need to be collected to determine the number of moles of gas in a sample of gas in asealed container?WeightVolumepressuremolar masstemperatureMassDensity

### Answers

**Answer**:

Volume, pressure and temperature.

**Explanation**:

In order to determine the number of moles of a gas sample, we need to collect information about the **volume**, **pressure** and **temperature** of the gas, because we can replace those values in the Ideal Gases law formula, and calculate the number of moles:

[tex]P*V=n*R*T[/tex]

In that formula, we will use the constant of the ideal gases R (0.082 atm.L/mol.K), so we have to make sure that all the collected information has the units atm, liters and Kelvin.

How are the temperature, pressure, amount and volume of gas related to each other in the gas laws?Hypotheses:

### Answers

Talking about ideal gases, we can espress the following relations:

This table tells us that:

1. When temperature is constant, pressure and volume are inversely proportional. This means that when pressure decreases, volume increases and when pressure increases, volume decreases.

2. When pressure is constant, volume and temperature are directly proportional. This means that if volume increases, temperature increases and if volume decreases, temperature also does.

3. When volume is constant, pressure and temperature are directly proportional. This means that if pressure increases, temperature increases and if presure decreases, temperature also does.

Is gunpowder a hom*ogenous mixture or a heterogenous mixture? Explain why.

### Answers

Gunpowder is a heterogenous mixture,

Reason : the composiotion of the mixture is not uniform throughout, the mixture can be separated by a suitable method , and finally , it composes of charcoal, sulfur and potassium nitrate which is not hom*ogeneous mixture.

gamma radiation a positive beta particle an alpha particle a negative beta particle

### Answers

When the nucleus increases its charge by one after emitting a particle, it means this particle is beta, specificallt, an electron called a negative beta particle. Basically, a beta particle forms when a netruon changes to a proton and a high-energy electron, the proton stays in the nuclues, and the electron is released as beta radiation. When this situation occurs, the mas number stays the same, the atomic number increases by 1, and the nuclear charge increases by 1.

Therefore, the answer is **a negative beta particle.**

Student AppChemistry B-ActivitiesType French accents-online Fr X12 Cultural Group 1 elements have an average electronegativity of 0.84 (not including hydrogen). Group 17 elements have an average electronegativity of 2.99. These two groups often form bonds. Given thisinformation, which kind of bond will they likely form (ionic or covalent, and what evidence supports your claim? If it is ionic then include which group gives up its electron to the other group in 3-5 sentences

### Answers

One way to determine the type of bond that forms is by checking the difference in electronegativity of the elements. When the difference in electronegativity is **less than 1.7**, the bond formed will be a **covalent bond**, since neither element is capable of completely taking electrons from the other, and therefore they are shared.

When the difference is **greater than 1.7**, one of the elements is much more electronegative than the other, so they will not share electrons but one element will give its electrons to the other, this is an **ionic bond**. Now let's see the difference of electronegativities of the elements of these groups.

Difference of electronegativities: 2.99-0.84=**2.15**

If the electronegativity difference is greater than 1.7, therefore the bond will be an ionic bond. In addition, the most electronegative element will be the one that takes the electrons and the other group will donate them.

In summary, the answer would be:

**The bond between group 1 and group 17 of the periodic table will be an ionic bond. Since the electronegativity difference is greater than 1.7. Group 1 will give its electron to the elements of group 17, since group 17 elements are more electronegative.**

which of the first long is true for water molecule

### Answers

**Answer:**

[tex]D[/tex]

**Explanation:**

Here, we want to select the correct option for a water molecule

In a water molecule, the atoms present are 2 hydrogen atoms and 1 oxygen atom

While the hydrogen is positive, the oxygen is negative

Thus, from the list of options given, the oxygen atom is slightly negative in charge is the correct option

Use the chart to answer the question. Given the bond energy below which bond is the weakest? Which bond is most stable?

### Answers

**Answer**

**C-Cl is the weakest bond** in the chart.

**H-F is the most stable bond **in the chart

**Explanation**

As bond strength increases, the atoms in the bond are pulled more tightly together. Therefore, generally, as the bond energy increases, the bond length decreases. The strength of a bond between two atoms increases as the number of electron pairs in the bond increases.

So, the bond energy is directly related to the strength of a chemical bond. High bond energy means that a bond is strong and the molecule that contains that bond is likely to be stable and less reactive**.**

Hence, **C-Cl is the weakest bond** in the chart because it has the least bond energy (339 kJ/mol) and **H-F is the most stable bond **in the chart because it has the highest bond energy (565 kJ/mol).

2Li + Cl₂ → 2 LiCl Did lithium undergo oxidation or reduction?Did chlorine undergo oxidation of reduction?

### Answers

*Explanation:*

According to the next equation,

2Li + Cl₂ → 2 LiCl (completed and balanced)

-------

The oxidation state of each element changes as follows:

*Li) goes from 0 to +1 *

[tex]2Li^0=>\text{ Li}^{+1}+\text{ 2e}^{-1}[/tex]

*Cl) goes from 0 to -1*

[tex]2Cl^0+2e^{-1}=>2Cl^{-1}[/tex]

(these equations above are the half-reactions)

Therefore,

**Answer: **

**Lithium undergo oxidation**

**Chlorine undergo reduction**

Why do different elements have different emission spectrums?

### Answers

**Answer: Various aspects have various ranges cause they have various numbers of protons, and various numbers and plans of electrons.**

**Explanation:**

3.135 g of Ice is placed in a beaker of water. The water temperature in the beaker is 67 °C. After all the icemelts, the final water temperature in the beaker is 19.7 °C. 4 ptsHeat of fusion for water - 334 J/g. Specific heat of water 4.184 J/g °C. T2-T1 - 47.3°C.Note there are a couple different ways to solve this problem() Determine the initial volume of water in the beaker (before the ice was added),(b) Determine the final volume of water in the beaker (after all the ice has melted),.

### Answers

**Explanation:**

We have 135 g of ice and we place it inside a beaker with hot water. The final temperature of the mixture is 19.7 °C, so the ice will cool the hot water.

The ice will melt and its temperature will increase from 0°C to 19.7 °C (if we suppose that the initial temperature of ice is 0°C).

First we have to determine the amount of energy that the ice absorbed to melt.

**ΔHf = Cf * m**

Where ΔHf is the amount of energy that the ice will absorb, Cf is the heat of fusion and m is the mass of ice in this case.

Cf = 334 J/g m = 135 g

ΔHf = Cf * m

ΔHf = 334 J/g * 135 g

**ΔHf = 45090 J**

Once the ice is melted, that sample of water will increase its temperature from 0 °C to 19.7 °C. Let's find the amount of heat that it is necessary to do that.

**Q = m * C * ΔT**

Where Q is the amount of heat that the water will absorb, C is the specific heta of water and ΔT is the change in temperature.

Q₁ = m * C * ΔT

Q₁ = 135 g * 4.184 J/(g°C) * (19.7 °C - 0.0 °C)

**Q₁ = 11127 J**

The total amount of energy that the ice will absorb to go from solid ice at 0°C to liquid water at 19.7 °C is:

Qice = Q₁ + ΔHf

Qice = 11127 J + 45090 J

**Qice = 56217 J**

The ice is absorbing energy from the hot water that was in the beaker. So the heat that the ice gained is the same amount of heat that the hot water released with opposite sign.

Qice = - Qhw

**Qhw = -56217 J**

The heat that the hot water gave to the ice can be calculated using this formula.

**Qhw = m * C * ΔT**

We can replace the values that we already know and solve that equation for m to get the initial volume of water in the beaker.

Qhw = m * C * ΔT

- 56217 J = m * 4.184 J/(g *°C) * (19.7 °C - 67.0 °C)

m = -56217 J /(4.184 J/(g*°C) * (-47.3 °C)

**m = 284 g**

Since the density of water is 1 g/mL, we can convert the mass of water into volume.

Initial volume = 284 g / (1 g/mL)

**Initial volume = 284 mL**

Now we know the volume of water that was in the beaker before the ice is added, and we are given the mass of ice. We can find the final volume of water in the baker.

Final volume = initial volume + volume from ice

Final volume = 284 mL + 135 g /(1 g/mL)

**Final volume = 419 mL**

**Answer:**** **

**a) The initial volume of water in the beaker was 284 mL.**

**b) The final volume of water in the beaker is 419 mL.**

Which term describes this reaction?HCH2CH2O eliminationO substitutionCH21CH2C=CHHCH2CH2 CH₂ CH2HCH2 CH2CH₂ CH2CH₂ CH₂

### Answers

We see that a molecule unites with itself to form a long chain of the same molecule, this is called polymerization.

Now, an addition polymerization is when the whole molecule is part of the polymer and a condensation polymerization refers to when a part of the molecule is lost and is not part of the polymer.

In this case, the carbon double bond is broken to form the polymer, both CH2=CH2 molecules will be part of the polymer, so this is an addition polymerization reaction.

Answer: **Addition polymerization**

I’m confused on how to find the boiling based on formula

### Answers

The boiling point is related to the energy required for the molecules of a compound to go from a liquid state to a gaseous state. The higher the energy required, the higher the boiling point.

Now, this energy will depend on the number of bonds in the molecule and their bond types. The longer the molecule, the more bonds it will have and the more energy it will need. Also, a double bond will require more energy than a single bond.

Let's see then the types of molecules we have. We have 4 molecules that correspond to organic acids, all these acids have single bonds, so on that side, the boiling points would be similar. What changes is the length of the chain that accompanies the carboxylic group (COOH).

Let's count the number of atoms of each element in the molecules:

In the table we see the number of moles, the higher the number of carbon atoms, the longer the chain will be and the boiling point will be higher. The hydrogen atoms will depend on the carbon atoms since they are attached to them, so we can simply rely on the number of carbon atoms to order the compounds.

Therefore, the order of the acids from the highest boiling point to the lowest boiling point will be:

**1.Octadecanoic acid**

**2.Octanoic acid**

**3.Butanoic acid**

**4.Methanoic acid**

How many milliliters of a 0.8 M solution of citric acid would be needed to react with 15 grams of baking soda? citric acid (C6H8O7) baking soda (NaHCO3)the equation that demonstrates reaction:C6H8O7 + 3NaHCO3 → Na3C6H5O7 + 3H2O + 3CO2

### Answers

Answer:

**74.4mL**

Explanations:

Given the reaction between **citric acid and baking soda e**xpressed as:

[tex]C_6H_8O_7+3NaHCO_3\rightarrow Na_3C_6H_5O_7+3H_2O+3CO_2[/tex]

**Given the following** parameters

Mass of baking soda = 15grams

**Determine the moles **of baking soda

[tex]\begin{gathered} moles\text{ of baking soda}=\frac{15}{84.007} \\ moles\text{ of baking soda}=0.1786moles \end{gathered}[/tex]

According to stoichiometry, 1 mole of citric acid reacted with 3 moles of baking soda, the **moles of citric acid required** will be:

[tex]\begin{gathered} moles\text{ of citric acid}=\frac{1mole\text{ of citric acid}}{3\cancel{moles\text{ of baking soda}}}\times0.1786\cancel{moles\text{ of baking soda}} \\ moles\text{ of citric acid}=0.0595moles \end{gathered}[/tex]

Determine the volume of citric acid

[tex]\begin{gathered} volume\text{ of citric acid}=\frac{mole}{molarity} \\ volume\text{ of citric acid}=\frac{0.0595}{0.8} \\ volume\text{ of citric acid}=0.0744L=74.4mL \end{gathered}[/tex]

Hence the required **volume of citric acid** is **74.4mL**

How many moles of sodium chlorate would be produced if 4.250 moles of oxygen react completely with sodium chloride? Balanced Chem. Eq.:

### Answers

**Answer: 2.125 moles of NaClO4 would be produced if 4.250 moles of O2 reacted completely with NaCl.**

Explanation:

The question requires us to calculate the amount of moles of sodium chlorate (NaClO4) that would be produced when 4.250 moles of oxygen (O2) react completely with sodium chloride (NaCl).

The unbalanced chemical equation for the reaction between O2 and NaCl to form NaClO4 can be written as:

[tex]NaCl+O_2\rightarrow NaClO_4[/tex]

Note that the equation above is not balanced: we need to adjust the amount of O atoms.

There are 2 O atoms on the left side, while there are 4 O atoms on the right side, thus we can adjust the coefficient of O2 from 1 to 2. The balanced chemical equation can be written as:

[tex]NaCl+2O_2\operatorname{\rightarrow}NaClO_4[/tex]

From the balanced chemical equation, we can see that 2 moles of O2 are necessary to produce 1 mol of NaClO4. With this information, we can calculate how many moles of NaClO4 would be obtained from 4.250 moles of O2:

*2 mol O2 --------------------------- 1 mol NaClO4*

*4.250 mol O2 -------------------- x*

Solving for x, we'll have:

[tex]x=4.250mol\text{ O}_2\times\frac{1mol\text{ NaClO}_4}{2mol\text{ O}_2}=2.125mol\text{ NaClO}_4[/tex]

Therefore, **2.125 moles of NaClO4 would be produced if 4.250 moles of O2 reacted completely with NaCl**.